Optimal. Leaf size=334 \[ \frac{2 b c-a d}{7 a^3 x^7}-\frac{c}{10 a^2 x^{10}}-\frac{a^2 e-2 a b d+3 b^2 c}{4 a^4 x^4}-\frac{\sqrt [3]{b} \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \left (-4 a^3 f+7 a^2 b e-10 a b^2 d+13 b^3 c\right )}{9 a^{16/3}}-\frac{\sqrt [3]{b} \tan ^{-1}\left (\frac{\sqrt [3]{a}-2 \sqrt [3]{b} x}{\sqrt{3} \sqrt [3]{a}}\right ) \left (-4 a^3 f+7 a^2 b e-10 a b^2 d+13 b^3 c\right )}{3 \sqrt{3} a^{16/3}}+\frac{\sqrt [3]{b} \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right ) \left (-4 a^3 f+7 a^2 b e-10 a b^2 d+13 b^3 c\right )}{18 a^{16/3}}+\frac{b x^2 \left (a^3 (-f)+a^2 b e-a b^2 d+b^3 c\right )}{3 a^5 \left (a+b x^3\right )}+\frac{a^3 (-f)+2 a^2 b e-3 a b^2 d+4 b^3 c}{a^5 x} \]
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Rubi [A] time = 0.948896, antiderivative size = 334, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 8, integrand size = 30, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.267 \[ \frac{2 b c-a d}{7 a^3 x^7}-\frac{c}{10 a^2 x^{10}}-\frac{a^2 e-2 a b d+3 b^2 c}{4 a^4 x^4}-\frac{\sqrt [3]{b} \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \left (-4 a^3 f+7 a^2 b e-10 a b^2 d+13 b^3 c\right )}{9 a^{16/3}}-\frac{\sqrt [3]{b} \tan ^{-1}\left (\frac{\sqrt [3]{a}-2 \sqrt [3]{b} x}{\sqrt{3} \sqrt [3]{a}}\right ) \left (-4 a^3 f+7 a^2 b e-10 a b^2 d+13 b^3 c\right )}{3 \sqrt{3} a^{16/3}}+\frac{\sqrt [3]{b} \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right ) \left (-4 a^3 f+7 a^2 b e-10 a b^2 d+13 b^3 c\right )}{18 a^{16/3}}+\frac{b x^2 \left (a^3 (-f)+a^2 b e-a b^2 d+b^3 c\right )}{3 a^5 \left (a+b x^3\right )}+\frac{a^3 (-f)+2 a^2 b e-3 a b^2 d+4 b^3 c}{a^5 x} \]
Antiderivative was successfully verified.
[In] Int[(c + d*x^3 + e*x^6 + f*x^9)/(x^11*(a + b*x^3)^2),x]
[Out]
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Rubi in Sympy [A] time = 162.534, size = 326, normalized size = 0.98 \[ - \frac{x \left (\frac{a^{3} f}{x^{11}} - \frac{a^{2} b e}{x^{11}} + \frac{a b^{2} d}{x^{11}} - \frac{b^{3} c}{x^{11}}\right )}{3 a b^{3} \left (a + b x^{3}\right )} - \frac{a^{2} f - a b e + b^{2} d}{10 a b^{3} x^{10}} + \frac{2 a^{2} f - 2 a b e + b^{2} d}{7 a^{2} b^{2} x^{7}} - \frac{3 a^{2} f - 2 a b e + b^{2} d}{4 a^{3} b x^{4}} + \frac{3 a^{2} f - 2 a b e + b^{2} d}{a^{4} x} - \frac{\sqrt [3]{b} \left (3 a^{2} f - 2 a b e + b^{2} d\right ) \log{\left (\sqrt [3]{a} + \sqrt [3]{b} x \right )}}{3 a^{\frac{13}{3}}} + \frac{\sqrt [3]{b} \left (3 a^{2} f - 2 a b e + b^{2} d\right ) \log{\left (a^{\frac{2}{3}} - \sqrt [3]{a} \sqrt [3]{b} x + b^{\frac{2}{3}} x^{2} \right )}}{6 a^{\frac{13}{3}}} - \frac{\sqrt{3} \sqrt [3]{b} \left (3 a^{2} f - 2 a b e + b^{2} d\right ) \operatorname{atan}{\left (\frac{\sqrt{3} \left (\frac{\sqrt [3]{a}}{3} - \frac{2 \sqrt [3]{b} x}{3}\right )}{\sqrt [3]{a}} \right )}}{3 a^{\frac{13}{3}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((f*x**9+e*x**6+d*x**3+c)/x**11/(b*x**3+a)**2,x)
[Out]
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Mathematica [A] time = 0.343361, size = 319, normalized size = 0.96 \[ \frac{-\frac{180 a^{7/3} (a d-2 b c)}{x^7}-\frac{126 a^{10/3} c}{x^{10}}-\frac{315 a^{4/3} \left (a^2 e-2 a b d+3 b^2 c\right )}{x^4}-\frac{420 \sqrt [3]{a} b x^2 \left (a^3 f-a^2 b e+a b^2 d-b^3 c\right )}{a+b x^3}-\frac{1260 \sqrt [3]{a} \left (a^3 f-2 a^2 b e+3 a b^2 d-4 b^3 c\right )}{x}+140 \sqrt [3]{b} \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \left (4 a^3 f-7 a^2 b e+10 a b^2 d-13 b^3 c\right )-140 \sqrt{3} \sqrt [3]{b} \tan ^{-1}\left (\frac{1-\frac{2 \sqrt [3]{b} x}{\sqrt [3]{a}}}{\sqrt{3}}\right ) \left (-4 a^3 f+7 a^2 b e-10 a b^2 d+13 b^3 c\right )+70 \sqrt [3]{b} \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right ) \left (-4 a^3 f+7 a^2 b e-10 a b^2 d+13 b^3 c\right )}{1260 a^{16/3}} \]
Antiderivative was successfully verified.
[In] Integrate[(c + d*x^3 + e*x^6 + f*x^9)/(x^11*(a + b*x^3)^2),x]
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Maple [A] time = 0.025, size = 575, normalized size = 1.7 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((f*x^9+e*x^6+d*x^3+c)/x^11/(b*x^3+a)^2,x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((f*x^9 + e*x^6 + d*x^3 + c)/((b*x^3 + a)^2*x^11),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.247194, size = 632, normalized size = 1.89 \[ \frac{\sqrt{3}{\left (70 \, \sqrt{3}{\left ({\left (13 \, b^{4} c - 10 \, a b^{3} d + 7 \, a^{2} b^{2} e - 4 \, a^{3} b f\right )} x^{13} +{\left (13 \, a b^{3} c - 10 \, a^{2} b^{2} d + 7 \, a^{3} b e - 4 \, a^{4} f\right )} x^{10}\right )} \left (\frac{b}{a}\right )^{\frac{1}{3}} \log \left (b x^{2} - a x \left (\frac{b}{a}\right )^{\frac{2}{3}} + a \left (\frac{b}{a}\right )^{\frac{1}{3}}\right ) - 140 \, \sqrt{3}{\left ({\left (13 \, b^{4} c - 10 \, a b^{3} d + 7 \, a^{2} b^{2} e - 4 \, a^{3} b f\right )} x^{13} +{\left (13 \, a b^{3} c - 10 \, a^{2} b^{2} d + 7 \, a^{3} b e - 4 \, a^{4} f\right )} x^{10}\right )} \left (\frac{b}{a}\right )^{\frac{1}{3}} \log \left (b x + a \left (\frac{b}{a}\right )^{\frac{2}{3}}\right ) - 420 \,{\left ({\left (13 \, b^{4} c - 10 \, a b^{3} d + 7 \, a^{2} b^{2} e - 4 \, a^{3} b f\right )} x^{13} +{\left (13 \, a b^{3} c - 10 \, a^{2} b^{2} d + 7 \, a^{3} b e - 4 \, a^{4} f\right )} x^{10}\right )} \left (\frac{b}{a}\right )^{\frac{1}{3}} \arctan \left (-\frac{2 \, \sqrt{3} b x - \sqrt{3} a \left (\frac{b}{a}\right )^{\frac{2}{3}}}{3 \, a \left (\frac{b}{a}\right )^{\frac{2}{3}}}\right ) + 3 \, \sqrt{3}{\left (140 \,{\left (13 \, b^{4} c - 10 \, a b^{3} d + 7 \, a^{2} b^{2} e - 4 \, a^{3} b f\right )} x^{12} + 105 \,{\left (13 \, a b^{3} c - 10 \, a^{2} b^{2} d + 7 \, a^{3} b e - 4 \, a^{4} f\right )} x^{9} - 15 \,{\left (13 \, a^{2} b^{2} c - 10 \, a^{3} b d + 7 \, a^{4} e\right )} x^{6} - 42 \, a^{4} c + 6 \,{\left (13 \, a^{3} b c - 10 \, a^{4} d\right )} x^{3}\right )}\right )}}{3780 \,{\left (a^{5} b x^{13} + a^{6} x^{10}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((f*x^9 + e*x^6 + d*x^3 + c)/((b*x^3 + a)^2*x^11),x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((f*x**9+e*x**6+d*x**3+c)/x**11/(b*x**3+a)**2,x)
[Out]
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GIAC/XCAS [A] time = 0.217663, size = 590, normalized size = 1.77 \[ -\frac{{\left (13 \, b^{4} c \left (-\frac{a}{b}\right )^{\frac{1}{3}} - 10 \, a b^{3} d \left (-\frac{a}{b}\right )^{\frac{1}{3}} - 4 \, a^{3} b f \left (-\frac{a}{b}\right )^{\frac{1}{3}} + 7 \, a^{2} b^{2} \left (-\frac{a}{b}\right )^{\frac{1}{3}} e\right )} \left (-\frac{a}{b}\right )^{\frac{1}{3}}{\rm ln}\left ({\left | x - \left (-\frac{a}{b}\right )^{\frac{1}{3}} \right |}\right )}{9 \, a^{6}} - \frac{\sqrt{3}{\left (13 \, \left (-a b^{2}\right )^{\frac{2}{3}} b^{3} c - 10 \, \left (-a b^{2}\right )^{\frac{2}{3}} a b^{2} d - 4 \, \left (-a b^{2}\right )^{\frac{2}{3}} a^{3} f + 7 \, \left (-a b^{2}\right )^{\frac{2}{3}} a^{2} b e\right )} \arctan \left (\frac{\sqrt{3}{\left (2 \, x + \left (-\frac{a}{b}\right )^{\frac{1}{3}}\right )}}{3 \, \left (-\frac{a}{b}\right )^{\frac{1}{3}}}\right )}{9 \, a^{6} b} + \frac{b^{4} c x^{2} - a b^{3} d x^{2} - a^{3} b f x^{2} + a^{2} b^{2} x^{2} e}{3 \,{\left (b x^{3} + a\right )} a^{5}} + \frac{{\left (13 \, \left (-a b^{2}\right )^{\frac{2}{3}} b^{3} c - 10 \, \left (-a b^{2}\right )^{\frac{2}{3}} a b^{2} d - 4 \, \left (-a b^{2}\right )^{\frac{2}{3}} a^{3} f + 7 \, \left (-a b^{2}\right )^{\frac{2}{3}} a^{2} b e\right )}{\rm ln}\left (x^{2} + x \left (-\frac{a}{b}\right )^{\frac{1}{3}} + \left (-\frac{a}{b}\right )^{\frac{2}{3}}\right )}{18 \, a^{6} b} + \frac{560 \, b^{3} c x^{9} - 420 \, a b^{2} d x^{9} - 140 \, a^{3} f x^{9} + 280 \, a^{2} b x^{9} e - 105 \, a b^{2} c x^{6} + 70 \, a^{2} b d x^{6} - 35 \, a^{3} x^{6} e + 40 \, a^{2} b c x^{3} - 20 \, a^{3} d x^{3} - 14 \, a^{3} c}{140 \, a^{5} x^{10}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((f*x^9 + e*x^6 + d*x^3 + c)/((b*x^3 + a)^2*x^11),x, algorithm="giac")
[Out]